0=-16t^2-20t+110

Solution for 0=-16t^2-20t+110 equation:

0=-16t^2-20t+110

We move all terms to the left:

0-(-16t^2-20t+110)=0

We add all the numbers together, and all the variables

-(-16t^2-20t+110)=0

We get rid of parentheses

16t^2+20t-110=0

a = 16; b = 20; c = -110;
Δ = b2-4ac
Δ = 202-4·16·(-110)
Δ = 7440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7440}=\sqrt{16*465}=\sqrt{16}*\sqrt{465}=4\sqrt{465}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{465}}{2*16}=\frac{-20-4\sqrt{465}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{465}}{2*16}=\frac{-20+4\sqrt{465}}{32}
$